OK, I'm planning on adding one large access hole to the top forward skin on my -7A (tipup). It will be a large access hole and consume as much of the space between the tipup support ribs as possible. Since it's going to be a single panel rather than two smaller panels (as others have done) it will span (and be screwed to) the center rib. I'm trying to calculate the number of fasteners (rivets and screws) to meet accepted practices and not compromise the strength of this skin.
According to AC 43.13-1B, Table 4-10, I need 6.9 3/32 rivets per inch (RPI) all the way around the access hole. Using three rows of rivets on 4D spacing (3D spacing row-to-row) results in 8.33 RPI. So far so good.
I plan to use #8 screws to attach the panel (AN509-8R8 or MS24694-S5).
To check the strength of the various interfaces, I have five sets of calculations:
1. Shear strength of rivets
Alloy 2117-T4
Shear strength 26,000 psi
Tensile strength 38,000 psi
Rivets per inch 6.9 (this is conservative since actual will be 8.33 RPI)
Shear strength of rivets per inch = 6.9 * (3/64)^2 * pi * 26,000 = 1238 lb/in
2. Bearing strength of skin on rivets
Alloy 2024-T3
Tensile strength 58,000 psi
Rivet dia = 3/32
Skin thickness .025
Rivets per inch 6.9 (this is conservative since actual will be 8.33 RPI)
Skin bearing strength per inch = 3/32 * 6.9 * .025 * 58,000 = 938 lb/in
3. Tensile strength of skin (this applies to both the top skin and the doubler)
Alloy 2024-T3
Skin thickness .025
Tensile strength 58,000 psi
4D rivet spacing results in 75% material remaining
Tensile strength of skin per inch = .025 * 1 * 75% * 58,000 = 1087 lb/in
4. Shear strength of screws
Screw spec AN509-8R8 (MS24694-S5)
Tensile strength 125,000 psi
Shear strength = 58% * Tensile strength = 72,500 psi (per Young's Theorem aka Distortion Energy Theorem aka Von Mises Theorem)
Diameter of screw = .164 inch
Shear strength of a single screw = (.164/2)^2 * pi * 125,000 * 58% = 2640 lb/screw
5. Bearing strength of skin on screws
Alloy 2024-T3
Tensile strength 58,000 psi
Diameter of screw .164 inch
Skin thickness .025
Skin bearing strength per screw = .164 * .025 * 58,000 = 238 lb/screw![Eek! :eek: :eek:](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
So everything was looking good until I performed calculation #5. In order to make the screw interface as strong as the next weakest link (calc #2), I'll need 4 screws per inch. That "feels" like way too many screws, so I think using the grip diameter of the screw in calculation #5 may be way too conservative.
So here's the question: Since the screw locations will have nested dimples, is it reasonable to use a different diameter (larger than .164) to calculate the bearing strength of the skin on the screws? How do you aero engineers do this?
Thanks.
OK...I checked with a fellow engineer. He had some info that was helpful. He looked in one of his reference books, "Analysis & Design of Flight Vehicle Structures" by E.F. Bruhn and although he couldn't find the ultimate shear strength of a #8 dimpled hole, he found that a 5/36 flush dimpled hole was good for 415lb. That's a lot better and it get's me down to about 2.25 screws per inch.
According to AC 43.13-1B, Table 4-10, I need 6.9 3/32 rivets per inch (RPI) all the way around the access hole. Using three rows of rivets on 4D spacing (3D spacing row-to-row) results in 8.33 RPI. So far so good.
I plan to use #8 screws to attach the panel (AN509-8R8 or MS24694-S5).
To check the strength of the various interfaces, I have five sets of calculations:
1. Shear strength of rivets
Alloy 2117-T4
Shear strength 26,000 psi
Tensile strength 38,000 psi
Rivets per inch 6.9 (this is conservative since actual will be 8.33 RPI)
Shear strength of rivets per inch = 6.9 * (3/64)^2 * pi * 26,000 = 1238 lb/in
2. Bearing strength of skin on rivets
Alloy 2024-T3
Tensile strength 58,000 psi
Rivet dia = 3/32
Skin thickness .025
Rivets per inch 6.9 (this is conservative since actual will be 8.33 RPI)
Skin bearing strength per inch = 3/32 * 6.9 * .025 * 58,000 = 938 lb/in
3. Tensile strength of skin (this applies to both the top skin and the doubler)
Alloy 2024-T3
Skin thickness .025
Tensile strength 58,000 psi
4D rivet spacing results in 75% material remaining
Tensile strength of skin per inch = .025 * 1 * 75% * 58,000 = 1087 lb/in
4. Shear strength of screws
Screw spec AN509-8R8 (MS24694-S5)
Tensile strength 125,000 psi
Shear strength = 58% * Tensile strength = 72,500 psi (per Young's Theorem aka Distortion Energy Theorem aka Von Mises Theorem)
Diameter of screw = .164 inch
Shear strength of a single screw = (.164/2)^2 * pi * 125,000 * 58% = 2640 lb/screw
5. Bearing strength of skin on screws
Alloy 2024-T3
Tensile strength 58,000 psi
Diameter of screw .164 inch
Skin thickness .025
Skin bearing strength per screw = .164 * .025 * 58,000 = 238 lb/screw
So everything was looking good until I performed calculation #5. In order to make the screw interface as strong as the next weakest link (calc #2), I'll need 4 screws per inch. That "feels" like way too many screws, so I think using the grip diameter of the screw in calculation #5 may be way too conservative.
So here's the question: Since the screw locations will have nested dimples, is it reasonable to use a different diameter (larger than .164) to calculate the bearing strength of the skin on the screws? How do you aero engineers do this?
Thanks.
OK...I checked with a fellow engineer. He had some info that was helpful. He looked in one of his reference books, "Analysis & Design of Flight Vehicle Structures" by E.F. Bruhn and although he couldn't find the ultimate shear strength of a #8 dimpled hole, he found that a 5/36 flush dimpled hole was good for 415lb. That's a lot better and it get's me down to about 2.25 screws per inch.
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