NEW! Ultimate C/S Prop Wrench Anti Splat Aero

[L.Adamson]

Originally Posted by nauga

*sigh*

If I have a 12" torque wrench and I apply a 80 lb force at the grip there will be a 80 ft-lb torque at the head. If I add a 3" extension (0.25 ft) straight out from the head that 80 lb will still produce 80 ft-lb at the head but it will produce 100 ft-lb at the end of the extension. That's what everyone wants. Problem is, if I use an 18" wrench, I will apply a 53.3 lb force at the handle to get 80 ft-lb at the wrench head. The torque at the bolt will be 53.3lb*(1.5+0.25 ft), or 93.3 ft-lb.

Might be within tolerances, might not. It's better to know than to guess.

You're still incorrect. The difference is where the 3" extention is applied. If it's between the nut & wrench head, then the .80 applies. It doesn't matter how long the handle of the wrench is, even with cheater bars, if the 3" between the nut and wrench head stays at 3".

As I previously said, that nut is still going to turn the same distance
to satisfy it's torque setting, wheather you apply 80 lbs or 53.3 pounds at the end of the handle, depending on length. Additional length of handle, only changes the required amount of force, that you apply to turn that nut the same amount of degrees.............as long as the original 3" remains the same.

[erich weaver]

Originally Posted by PCHunt

The reason length doesn't matter is that the torque wrench is indicating the torque on the nut, and not the force on the end of the wrench.

A wrench handle can be any length, and if the torque reading is calibrated at the nut end of the wrench, it will tell you the torque on the nut, which is what you want.

So, wrench #1 is 10 feet long, with a dial that indicates ft-lbs (or more correctly lb-ft) at the NUT. if you want 100 pounds of torque, you would apply a force of 10 lbs at the handle, and the dial would read 100. (10 feet X 10 lbs = 100 ft-lbs)

Wrench #2 is 1 foot long, with a dial that reads torque at the NUT. If you want 100 lbs of torque, you would apply a force of 100 lbs at the HANDLE, and the dial would read 100. (1 foot X 100 lbs = 100 ft-lbs)

You guys are confusing the nut torque with the force needed at the handle.

All torque wrenches read TORQUE AT THE NUT, not force on the end of the handle.

That's why the length of the handle doesn't matter for torque wrenches.

Taking all bets!

HEY! I get it now, thanks to a few of the posts above. When you set the torque wrench for 100 ft lbs, by definition, you are going to have a force of 100 lbs applied 1 foot from the end of the wrench regardless of how long your wrench is, so that's where the 12 inches comes from. When you add the 3 inch extension, you are applying that 100 lbs to the close end of the extension, but more than 100 lbs to the nut at the far end of the extension. Hence the multiplier of 12/(12 + 3) = 0.8

WOO HOO! Now I can sleep.

Erich

[DarylT]

Everyone agrees its a great tool. Lets go build some RV's!!!! Then we can use the tool.

[PerfTech]

Originally Posted by DarylT

Everyone agrees its a great tool. Lets go build some RV's!!!! Then we can use the tool.

Now this guy has the right idea, so
BUY! BUY! BUY! BUY!
Our operators are standing buy. Thanks, Allan

[Lux Wrangler]

Let's assume I own a torque wrench which is two feet long. If I wanted to torque a fastener to 100 Ft-lbs. I would apply 50 lbs.

50lbs. * 2 ft. = 100 ft-lbs.

I buy the tool and follow the directions. I want 100 ft-lbs. of torque at the fastener, so I would set the wrench to 80 ft-lbs. (.8 * 100 = 80). That means I would apply 40 pounds of force to my end of the torque wrench, or 80 ft-lbs. to the drive end of the torque wrench.

40 lbs. * 2 ft. = 80 ft-lbs. which is the recommended torque wrench setting.

Now I am ready to proceed. I attach the tool which adds 3 inches, or 1/4 foot to the system. Now my system is 2.25 feet long. (2 for the wrench + .25 for the tool) I apply the 40 pounds force to the end of the tool and the wrench clicks. I now have applied 40 lbs. * 2.25 ft. = 90 ft-lbs.

[LifeofReiley]

And all this time I thought this was the Classified Section...

[gstone]

Now I am ready to proceed. I attach the tool which adds 3 inches, or 1/4 foot to the system. Now my system is 2.25 feet long. (2 for the wrench + .25 for the tool) I apply the 40 pounds force to the end of the tool and the wrench clicks. I now have applied 40 lbs. * 2.25 ft. = 90 ft-lbs.

No, because your wrench doubles your efforts first at the attach end of your torque wrench making it apply 80 lb feet there and the 3 inch extension adds 25 percent to that making 100 lbs.

It really works the way Allan says!!!

[tomwebster]

My head hurts!
Tom

[schristo@mac.com]

Apparently Allan is a marketing genius...

[Lux Wrangler]

I believe!

-Religion?

Now I am ready to proceed. I attach the tool which adds 3 inches, or 1/4 foot to the system. Now my system is 2.25 feet long. (2 for the wrench + .25 for the tool) I apply the 40 pounds force to the end of the tool and the wrench clicks. I now have applied 40 lbs. * 2.25 ft. = 90 ft-lbs.

-Science

No, because your wrench doubles your efforts first at the attach end of your torque wrench making it apply 80 lb feet there and the 3 inch extension adds 25 percent to that making 100 lbs....It really works the way Allan says!!!

-Religion?

.25 is not 25 percent of 2 feet, but 25 percent of 1 foot
- Science