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  #11  
Old 03-31-2011, 10:50 PM
koda2 koda2 is offline
 
Join Date: Mar 2007
Location: West Texas
Posts: 282
Default Dimensions

Gil,
You are correct in calling out my typo error, but depending on the flange, the bend radius and the rivet size, there may not be much margin for error. Some of the flanges I have had to work with were not 5/8, plus with a fairly generous bend radius. The flat was significantly less than the mold line.

I understand the drawing as showing the side of the rivet head beginning at a minimum point .030 from the edge of the bend radius.

By picking a line that allows a little extra margin than the minimum on each side, I am still in good shape if my drill point errs a bit, or God forbid, I screw up the rivet and have to go up a size. It has happened.

Centering the rivet hole, more or less, on the flat, seems to work best for me and meets the minimums with a little to spare.

Dave A.
6A build

Last edited by koda2 : 03-31-2011 at 10:52 PM. Reason: spelling error
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  #12  
Old 04-01-2011, 12:31 PM
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az_gila az_gila is offline
 
Join Date: Jan 2005
Location: 57AZ - NW Tucson area
Posts: 10,011
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Quote:
Originally Posted by koda2 View Post
....Centering the rivet hole, more or less, on the flat, seems to work best for me and meets the minimums with a little to spare.

Dave A.
6A build
OK... so you are a vote for "C" in post #1.

I think we have the entire spectrum covered in the responses...
__________________
Gil Alexander
EAA Technical Counselor, Airframe Mechanic
Half completed RV-10 QB purchased
RV-6A N61GX - finally flying
Grumman Tiger N12GA - flying
La Cholla Airpark (57AZ) Tucson AZ
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  #13  
Old 04-04-2011, 05:13 PM
John R. Graham John R. Graham is offline
 
Join Date: Dec 2010
Location: Alpharetta, GA
Posts: 88
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I went ahead and made measurements on two representative prepunched flanges from my RV7 kit. First, here's a slightly updated drawing:


The two parts were:
  • A wing rib. D turned out to be exactly half of A: (D = A / 2).
  • The vertical stabilizer spar. Here the observed centerline was moved towards the flange edge by about 2/3 of the radius, resulting in the rather ugly D = (A / 2) + 2*(A - C) / 3.
I'd note that the bend radius on the rib was rather tight whereas the bend radius on the spar was considerably greater. So far, I don't see an elegant, general rule that covers both. I guess I have my answer, though.

- John
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